A car moving with constant acceleration covers the distance between two points 60m apart in 6s

a) We can find the velocity of the car at the first point from the kinematic equation:

"d=\\dfrac{v_0+v}{2}t,""v_0=\\dfrac{2d}{t}-v=\\dfrac{2\\cdot 60\\ m}{6\\ s}-15\\ \\dfrac{m}{s}=5\\ \\dfrac{m}{s}."

b) We can find the acceleration of the car from another kinematic equation:

"v=v_0+at,""a=\\dfrac{v-v_0}{t}=\\dfrac{15\\ \\dfrac{m}{s}-5\\ \\dfrac{m}{s}}{6\\ s}=1.66\\ \\dfrac{m}{s^2}."

Answer:

a) "v_0=5\\ \\dfrac{m}{s}."

b) "a=1.66\\ \\dfrac{m}{s^2}."