Two particles A and B, of mass m and 2m respectively, are attached to the ends of a light

Two particles A and B, of mass m and 2m respectively, are attached to the ends of a light

Text Solution

Answer : (i) `sqrt(2ag)/(3)` (ii) `(3v)/(g)` (iii) `(2v)/(g)`

Solution : `2mg - T = 2m.a` ….(i) <br> `T - mg = m.a` ….(ii) <br> On solving eq. (i) & (ii) `a = (g)/(3)` <br> (a) `v_(B) = sqrt(u^(2) + 2as) = sqrt(0 + 2((g)/(3))a) = sqrt((2ag)/(3))` <br> (b) `s = ut + (1)/(2) t^(2), a = 0 + (1)/(2)((g)/(3)) t^(2), t = sqrt((6a)/(g)) = (3v)/(g)` <br> (c ) `t = (2v)/(g)` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ALN_PHY_C05_E01_162_S01.png" width="80%">