Open in App Suggest Corrections 1 Two numbers are x and y such that x > y.Now,x + y = 50 ….(i)And, y2 - x2 = 720 ⇒ (y - x)(y + x) = 720⇒ (y - x)(50) = 720⇒ y - x = 14.4 ….(ii) Adding (i) and (ii), we get2y = 64.4 ⇒ y = 32.2 Substituting the value of y in (i), we havex + 32.2 = 50⇒ x = 17.8 Thus, the two numbers are 17.8 and 32.2 respectively. Page 2Let the two numbers be x and y respectively.Then,x + y = 8 ….(i)⇒ x = 8 - yAnd, `1/x + 1/y = 8/15` ⇒ `[ y + x ]/[xy] = 8/15` ⇒ `8/(xy) = 8/15` .....[ From(1) ]⇒ xy = 15⇒ ( 8 - y )y = 15 ⇒ 8y - y2 = 15 ⇒ y2 - 8y + 15 = 0 ⇒ y2 - 3y - 5y + 15 = 0⇒ y( y - 3 ) - 5( y - 3 ) = 0⇒ ( y - 3 )( y - 5 ) = 0⇒ y = 3 or y = 5⇒ x = 5 or x = 3 Thus, the two numbers are 3 and 5 respectively. |