Page 2Text Solution Solution : Let the body C of mass 15 kg be held at a distance x from body A. as net gravitational force on C is zero, therefore, `F_(1)=F_(2)` <br> `(Gxx20xx15)/(x^(2))=(Gxx15xx40)/((10-x)^(2))` <br> `(1)/(x)=(sqrt2)/(10-x)` <br> `sqrt(2)x=10-x` <br> `1.414x+x=10` <br> `x=10/2.414=4.14m`. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_IX_V01_C03_E01_059_S01.png" width="80%"> A has more inertia than B. They will not have any inertia. B has more inertia than A. A and B have same inertia.
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