Write two energy losses that are associated with a transformer? how can we overcome these?

What is a transformer

A transformer can be considered as the most useful electrical device which has ever invented. It can change the magnitude of alternating current and voltage from one value to another and this useful property of a transformer is the major reason to use alternating current rather than the direct current. So electric power is generated transmitted and distributed in the form of alternating current. There are no moving parts for a transformer and they have high efficiency. The transformer is a device that is used to either raise or lower the voltage of an AC supply with a corresponding increase or decrease in current.

What causes losses in the transformer and how to reduce it

Mostly transformer energy loss is caused by winding and core losses. Transformer losses vary with loads, in order to design an energy-efficient transformer with a lower loss would require a larger core, good-quality silicon steel, or even amorphous steel for the core and thicker wire.

Transformer losses arise from

Winding losses

Current flowing through a winding conductor causes joule heating. When the frequency increases the skin effect and proximity effect causes the winding resistance, and hence increase in loss.

Core loss

The transformer core is crucial in creating the required magnetic circuit. By using a good quality of iron core, we could get a stronger magnetic circuit. The magnetic circuit is the reason for the interlinking of the flux between the windings. Iron loss arises in a transformer as the currents get induced in it while creating the magnetic circuit.

Hysteresis loss

Hysteresis loss is heat loss due to the continuous magnetic field reversal. Energy will be lost by reversing the magnetic field in the core as the magnetizing AC rises and falls and reverses direction. So when each time the magnetic field is reversed a small amount of energy is lost due to hysteresis within the core. We can reduce the hysteresis loss by choosing high-quality magnetic material.

Eddy current loss

Eddy current loss is due to the current flow within the core due to changing magnetic fields. The core has to be suitably designed to control them to the desired levels. In order to reduce the eddy current core can be made by stacking thin sheets together and this will reduce the eddy current. Eddy currents are formed in the metal transformer core and cause heating of the core. The eddy current loss is a complex function of the square of supply frequency and inverse square of material thickness. This loss can be reduced by making the core of a stack of plates electrically insulated from each other.

Stray loss

Stray loss can be considered as the combination of the core loss which is caused by the distortion of an air gap and the I2R loss which is by the non- uniform distribution of conductor current.

Mechanical loss

This type of loss is formed by the bearing friction, brush friction and windage loss and the windage loss includes the power required to circulate air through the machine.

Copper losses

Because of the ohmic resistance copper loss occurs in the primary and secondary windings and it can be checked by a short circuit test. This type of loss is depended upon the magnitude of the current which flows through the winding.

What is the efficiency of a transformer and maximum efficiency of a transformer

Transformer efficiency will increase with an increase in transformer capacity. Like most of the electrical machines, the efficiency of the transformer is defined as the ratio of the output power to the input power.

Power output= power input – total loss, Power input= power output + total losses

Efficiency = power output ÷ power input

The power measured in the primary and secondary windings will be close but it won’t be equal. There will always be a small power loss, which means that not all the energy is transferred from the primary to the secondary winding. The loss of energy is a measure of the transformer’s efficiency. The transformer’s efficiency is the ratio of real output power to real input power. The power rating of the load is the real output power, and the sum of output power plus the transformer loss is the input power.

Condition for maximum efficiency

The efficiency of transformer changes as the function of loading and power factor. The efficiency varies with the load when load increases efficiency increases, the below figure shows the five different efficiency curves for the five different conditions of lagging power factor. Maximum efficiency is achieved at about half load and the maximum efficiency at half load is attained by adjusting a balance between specific design variables related to magnetic core and conductors.

Write two energy losses that are associated with a transformer? how can we overcome these?

  • When there is no load, there won’t be any losses and the efficiency is zero because power out is zero.
  • Efficiency increase when there is a small application of load
  • Mostly maximum efficiency occurs at one-half load
  • For the same value of load current, efficiency decreases slightly with decreasing values of power factor, and at the same load point efficiency will be maximum

  • Share:

In any electrical machine, 'loss' can be defined as the difference between input power and output power. An electrical transformer is an static device, hence mechanical losses (like windage or friction losses) are absent in it. A transformer only consists of electrical losses (iron losses and copper losses). Transformer losses are similar to losses in a DC machine, except that transformers do not have mechanical losses.
Losses in transformer are explained below -

Eddy current loss and hysteresis loss depend upon the magnetic properties of the material used for the construction of core. Hence these losses are also known as core losses or iron losses.

  • Hysteresis loss in transformer: Hysteresis loss is due to reversal of magnetization in the transformer core. This loss depends upon the volume and grade of the iron, frequency of magnetic reversals and value of flux density. It can be given by, Steinmetz formula:
    Wh= ηBmax1.6fV (watts) where,   η = Steinmetz hysteresis constant

                 V = volume of the core in m3

  • Eddy current loss in transformer: In transformer, AC current is supplied to the primary winding which sets up alternating magnetizing flux. When this flux links with secondary winding, it produces induced emf in it. But some part of this flux also gets linked with other conducting parts like steel core or iron body or the transformer, which will result in induced emf in those parts, causing small circulating current in them. This current is called as eddy current. Due to these eddy currents, some energy will be dissipated in the form of heat.

Copper loss is due to ohmic resistance of the transformer windings.  Copper loss for the primary winding is I12R1 and for secondary winding is I22R2. Where, I1 and I2 are current in primary and secondary winding respectively, R1 and R2 are the resistances of primary and secondary winding respectively. It is clear that Cu loss is proportional to square of the current, and current depends on the load. Hence copper loss in transformer varies with the load.

Just like any other electrical machine, efficiency of a transformer can be defined as the output power divided by the input power. That is  efficiency = output / input .

Transformers are the most highly efficient electrical devices. Most of the transformers have full load efficiency between 95% to 98.5% . As a transformer being highly efficient, output and input are having nearly same value, and hence it is impractical to measure the efficiency of transformer by using output / input. A better method to find efficiency of a transformer is using, efficiency = (input - losses) / input = 1 - (losses / input).

Let,

Copper loss = I12R1

Iron loss = Wi

Write two energy losses that are associated with a transformer? how can we overcome these?

Hence, efficiency of a transformer will be maximum when copper loss and iron losses are equal.
That is Copper loss = Iron loss.


As we have seen above, ordinary or commercial efficiency of a transformer can be given as

Write two energy losses that are associated with a transformer? how can we overcome these?

But in some types of transformers, their performance can not be judged by this efficiency. For example, distribution transformers have their primaries energized all the time. But, their secondaries supply little load all no-load most of the time during day (as residential use of electricity is observed mostly during evening till midnight).That is, when secondaries of transformer are not supplying any load (or supplying only little load), then only core losses of transformer are considerable and copper losses are absent (or very little). Copper losses are considerable only when transformers are loaded. Thus, for such transformers copper losses are relatively less important.  The performance of such transformers is compared on the basis of energy consumed in one day.

Write two energy losses that are associated with a transformer? how can we overcome these?

All day efficiency of a transformer is always less than ordinary efficiency of it.