Write a Python program to accept two integers and check whether they are equal or not

C programming, exercises, solution: Write a C program to accept two integers and check whether they are equal or not.

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Input : num1 = 1233, num2 - 1233 Output : Same Input : num1 = 223, num2 = 233 Output : Not Same Recommended: Please try your approach on {IDE} first, before moving on to the solution. Method 1: The idea is to use XOR operator.

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Last update on August 09 2022 03:31:20 (UTC/GMT +8 hours)

Write a Python program to input two integers in a single line.

Sample Solution-1:

Python Code:

print("Input the value of x & y") x, y = map(int, input().split()) print("The value of x & y are: ",x,y)

Sample Output:

Input the value of x & y 2 4 The value of x & y are: 2 4

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Sample Solution-2:

Python Code:

a, b = [int(a) for a in input("Input the value of a & b: ").split()] print("The value of a & b are:",a,b)

Sample Output:

Input the value of a & b: 2 4 The value of a & b are: 2 4

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Split a String:

>>> sentence = 'this is, a python, tutorial, about, idioms.' >>> sentence.split(', ') ['this is', 'a python', 'tutorial', 'about', 'idioms.'] >>> sentence.split(', ', 2) ['this is', 'a python', 'tutorial, about, idioms.'] >>> sentence.rsplit(', ') ['this is', 'a python', 'tutorial', 'about', 'idioms.'] >>> sentence.rsplit(', ', 2) ['this is, a python, tutorial', 'about', 'idioms.']

Last update on August 09 2022 03:31:14 (UTC/GMT +8 hours)

Write a C program to accept two integers and check whether they are equal or not.

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Sample Solution:

C Code:

#include <stdio.h> void main() { int int1, int2; printf("Input the values for Number1 and Number2 : "); scanf("%d %d", &int1, &int2); if (int1 == int2) printf("Number1 and Number2 are equal\n"); else printf("Number1 and Number2 are not equal\n"); }

Sample Output:

Input the values for Number1 and Number2 : 15 15 Number1 and Number2 are equal

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How to format strings using printf() to get equal length in the output?

You can specify a width on string fields, e.g.

printf("%-20s", "initialization...");

And then whatever's printed with that field will be blank-padded to the width you indicate.

The - left-justifies your text in that field.

Ref : https://bit.ly/34DMOc3

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The following are not allowed to use

Comparison Operators
String function

Examples:

Input : num1 = 1233, num2 – 1233
Output : Same
Input : num1 = 223, num2 = 233
Output : Not Same

Method 1: The idea is to use the XOR operator. XOR of two numbers is 0 if the numbers are the same, otherwise non-zero.

#include <iostream>
using namespace std;
void areSame(int a, int b)
{



   if (a^b)
       cout << "Not Same";
   else
       cout << "Same";
}
int main()
{ 
   areSame(10, 20);
}

class GFG
{
    static void areSame(int a,int b)
    {
        if( (a ^ b) != 0 )
            System.out.println("Not Same");
        else
            System.out.println("Same");
    }
    public static void main(String args[])
    {
        areSame(10,20);
    }
}

def areSame(a, b):
   if (a ^ b):
       print("Not Same")
   else:
       print("Same")
areSame(10, 20)

using System;
class GFG
{
    static void areSame(int a, int b)
    {
        if( (a ^ b) != 0 )
          Console.Write("Not Same");
        else
          Console.Write("Same");
    }
    public static void Main()
    {
        areSame(10, 20);
    }
}

<?php

function areSame($a, $b)

{

if ($a ^ $b)

echo "Not Same";

else

echo "Same";

}

areSame(10, 20);

<script>
function areSame(a, b)
{
if (a^b)
    document.write("Not Same");
else
    document.write("Same");
}
areSame(10, 20);
</script>

Time Complexity: O(1)
Auxiliary Space: O(1)

Method 2: We can subtract the numbers. The same numbers yield 0. If the answer is not 0, the numbers are not the same.

#include <bits/stdc++.h>
using namespace std;
void areSame(int a, int b)
{
    if (!(a - b))
        cout << "Same";
    else
        cout << "Not Same";
}
int main()
{   
     areSame(10, 20);   
    return 0;
}

class GFG{
    static void areSame(int a, int b)
    {
        if ((a - b) == 0)
            System.out.println("Same");
        else
            System.out.println("Not Same");
    }
    public static void main(String args[])
    {   
        areSame(10, 20);   
    }
}

def areSame(a, b):
    if (not(a - b)):
        print ("Same")
    else:
        print ("Not Same")
areSame(10, 20)

using System;
class GFG
{
    static void areSame(int a, int b)
    {
        if ((a - b) == 0)
            Console.Write("Same");
        else
            Console.Write("Not Same");
    }
    public static void Main()
    {
        areSame(10, 20);
    }
}

<?php
function areSame($a, $b)
{
    if (!($a - $b))
        echo "Same";
    else
        echo "Not Same";
}
areSame(10, 20);
?>

<script>
function areSame(a , b)
{
    if ((a - b) == 0)
        document.write("Same");
    else
        document.write("Not Same");
    }
areSame(10, 20);
</script>

Time Complexity: O(1)
Auxiliary Space: O(1)

Method 3: The bitwise AND of one number and the complement of the other number is zero if they are the same, and non-zero if they are not the same.

Below is the implementation of the above approach:

#include <iostream>
using namespace std;
void areSame(int a, int b)
{
    if (a & (~b))
        cout << "Not Same" << endl;
    else
        cout << "Same" << endl;
}
int main()
{
    areSame(10, 20);
}

def areSame(a, b):
    if (a & ~b):
        print ("Not Same")
    else:
        print ("Same")
areSame(10, 10)
areSame(10, 20)

using System;
class GFG
{
  static void areSame(int a, int b)
  {
    if (Convert.ToBoolean(a & (~b)))
      Console.WriteLine("Not Same");
    else
      Console.WriteLine("Same");
  }
  public static void Main(string[] args)
  {
    areSame(10, 20);
  }
}

function areSame(a, b)
{
    if (a & (~b))
        console.log("Not Same");
    else
        console.log("Same");
}
areSame(10, 20);

Time Complexity: O(1)
Auxiliary Space: O(1)

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