Hide Solution(s) (i) F F=(Gm1 m2)/(2R)2=(Gm1 m2)/4R2=F/4 F=F/4 hence force thus becomes one-fourth of its initial force.Now, if it's tripledHence, F=(Gm1 m2)/(3R)2 F=(Gm1 m2)/9R2 F=F/9 hence, force becomes one-ninth of its initial force.(iii)If masses of both the objects are doubled, then F=R2(G2m12m2) F=4 F, Force will therefore be four times greater than its actual value. Didn't understand the solution? Ask a TutorDownload Filo and start learning with |