Two point charges 1 microcoulomb and 4 microcoulomb

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Text Solution

`4/3 m` from `1muC``2/3 m` from `1muC``4/3 m` from `4muC``2/3 m` from `4muC`

Answer : C

Solution : Here, `q_(1) = 4 muC = 4xx10^(-16)C` <br> `q_(2) = 1 muC = 10^(-6)C` <br> d = 2m <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_XII_V01_C01_S01_022_S01.png" width="80%"> <br> Let electric field of the system be zero at P, <br> where AP = r, <br> At P,`E_(1) = E_( 2)` <br> ` v :. (q_(1)xx1)/(4pi in_(0) r^(2)) = (q_(2)xx(1))/(4pi in_(0) (2-r)^(2))` <br> `(4)/(r^(2)) = (q_(2)xx1)/(4pi in_(0) (2-r)^(2)) or (2)/(r) = (1)/(2-r)` <br> ` r = 4 - 2r` <br> `3r = 4` <br> `r = 4//3 m`