Two particles each of mass m are moving in horizontal circle with same angular speed

Two particles each of mass m are moving in horizontal circle with same angular speed

T=mw^2r As we have r1=r2 and m also same therefore as the angular velocityalso same T1=T2

Two particles each of mass m are moving in horizontal circle with same angular speed

Two particles each of mass m are moving in horizontal circle with same angular speed

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Two particles each of mass m are moving in horizontal circle with same angular speed

Two particles each of mass m are moving in horizontal circle with same angular speed

This is very easy. You can get it by the photograph.

Two particles each of mass m are moving in horizontal circle with same angular speed

Two particles each of mass m are moving in horizontal circle with same angular speed

I know writing is incredeble but answer is straight hope it helps😄🙂

Two particles each of mass m are moving in horizontal circle with same angular speed

Two particles each of mass m are moving in horizontal circle with same angular speed

Two particles each of mass m are moving in horizontal circle with same angular speed

T1/T2 is 3/2 .💛

Two particles each of mass m are moving in horizontal circle with same angular speed

Two particles each of mass m are moving in horizontal circle with same angular speed

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Two particles each of mass m are moving in horizontal circle with same angular speed

Two particles each of mass m are moving in horizontal circle with same angular speed. If both string are of same lenght then the ratio of tension in string T1/T2 is (1)3/2 (2) 3 (3) 2 (4) 1/3

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