Social media cookies: We use social media cookies from Facebook, Twitter and Google to run Widgets, Embed Videos, Posts, Comments and to fetch profile information. Answer 1. (a) Let the total number of bad widgets be= A The total number of good widgets= 1000 –A If he takes test I, his total cost will be = Rs. 2(1000) + 25 X 0.8A + 50 X 0.2A If he takes test II, his total cost will be : Rs. 3(1000) + 25 X A According to the conditions given, testing will be worth is the cost of testing is less than the cost of penalty levied on the defective pieces. In order to figure out the answers, let us chart out all the options given in the answer options and build a table for the given values: From the above table, it is clear that if the number of defectives more than 100, the cost of testing is cheaper than the penalty. For 100 defectives, the cost of penalty is the same as that for testing. It is obvious that for number of defectives above 100 cost of any testing is cheaper than the penalty. Thus, below 100 defectives, the penalty cost is will less than the cost of testing and hence, it is not worth testing.Answer 2. (d) We can use the table above to figure out the answer. For 120 widgets, he should go for test I as it is cheaper. Answer 3. (c) We can use the table above to figure out the answer. From the table, we can find that if the number of defectives is between 200 & 400, he should go for Test II as it is cheaper. Answer 4. (a) Again, we use the table above. If there are 160 defectives, he should use test I as it is cheaper. Answer 5. (a) Using the table above, we can see that if there are 200 defective widgets in the lot, the cost for Test I or II is the same (Rs. 8000). Thus, Prakash may use either Test I or Test II.
Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample in Profit and loss, which is common for all the competitive exams. We have included Some questions that are repeatedly asked in exams!!!
25 Qs. 50 Marks 20 Mins
Given: Loss of a shopkeeper (Calculating on S.P) = 40% Formula Used: Loss % = (C.P - S.P)/C.P × 100 Calculation: Actual formula = Loss % = (C.P - S.P)/C.P × 100 But shopkeeper used incorrect formula = Loss% = (C.P - S.P)/S.P × 100 Let the S.P of a article be 100x, then C.P be 140x. C.P is higher than S.P, then loss = 140x - 100x ⇒ 40x Loss percentage = (40x/140x) × 100 ⇒ 200/7% ∴ Loss percent is 200/7%. India’s #1 Learning Platform Start Complete Exam Preparation
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