Let the KE be 'x' Therefore for body of mass 1kg = 1/2 X 1kg X v12= KE --(i) Again, KE= 1/2 X 4kg X v22---(ii) Comparing 1 and 2, We get =1/2 X 1kg X v12=1/2 X 4kg X v22 =v12/v22=4 = v1/v2= 2--(i) Mass of body 1/ mass of body 2 = 1/4---(ii) Multiplying (i) X (ii) =1/4 X 2 =1/2 = 1 : 2 Therefore ratio of momentum of 1: 2 = 1:2
Tardigrade - CET NEET JEE Exam App
© 2022 Tardigrade®. All rights reserved |