The product of two consecutive numbers is 19.

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The product of two consecutive integers is 19 more than their sum. Find the integers

The two consecutive integers can be written as:

x and x+1, where x is integer

The product of two consecutive integers is 19 more than their sum:

x(x + 1) = 19 + x + (x + 1)

by solving we find:

x1 = 5

x2 = -4

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for x1 = 5

5 + 1 = 6

for x2 = -4

-4 + 1 = -3

there are two solutions:

first solution: the numbers are 5 and 6

second solution: the numbers are -4 and -3

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The product of two consecutive numbers is 19.

The product of two consecutive numbers is 19.
The product of two consecutive numbers is 19.

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Amanda W.

asked • 02/04/17

The product of two consecutive integers is 19 more than their sum. Find the integers.

2 Answers By Expert Tutors

Let the integers be X, and X + 1

X(X + 1) = X + (X + 1) + 19

from which we get X = -4 and 5

There are two possible sets of solutions 

the integers are = -4 and -4 + 1 or -4 and -3  (negative integers)

or 5 and 5 + 1 or 5 and 6  (positive integers)

check: -4*-3 = -4 + -3 + 19 = 12 (proven)

            5 * 6 = 5 + 6 + 19 = 30 (proven)

The product of two consecutive numbers is 19.

Mark M. answered • 02/04/17

Mathematics Teacher - NCLB Highly Qualified

The two integers are "n" and "n + 1."

n(n + 1) = n + n + 1 + 19

Can you solve for "n" and answer the question?