The product of two consecutive integers is 19 more than their sum. Find the integers The two consecutive integers can be written as: x and x+1, where x is integer The product of two consecutive integers is 19 more than their sum: x(x + 1) = 19 + x + (x + 1) by solving we find: x1 = 5 x2 = -4 click here to see the step by step solution of the quadratic equation: for x1 = 5 5 + 1 = 6 for x2 = -4 -4 + 1 = -3 there are two solutions: first solution: the numbers are 5 and 6 second solution: the numbers are -4 and -3
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Write an equation and solve. The product of two consecutive integers is 19 more than their sum. Find the integers. The difference between the greatest and the least factor of 84 is 3×+10 = ?nonsense report Find f(x) if(f - g)(x) = 2x² – 2x and g(x) = x² − 1Pasagot po username: IntrovertDiarypassword: 123456 the set of all multiples of 2 x-9 what is the the value directions/instructions:it is important to simplify the equation by combining similar terms before deciding whether a given equation is quadratic or n … are the roots of a quadratic equation always be distinct numbers Quadratic equation help Problem 2: Your favorite dog groomer charges according to your dog’s weight (w). If your dog is 15 pounds and under, the groomer charges P200. If your … Amanda W. The product of two consecutive integers is 19 more than their sum. Find the integers. 2 Answers By Expert Tutors Let the integers be X, and X + 1 X(X + 1) = X + (X + 1) + 19 from which we get X = -4 and 5 There are two possible sets of solutions the integers are = -4 and -4 + 1 or -4 and -3 (negative integers) or 5 and 5 + 1 or 5 and 6 (positive integers) check: -4*-3 = -4 + -3 + 19 = 12 (proven) 5 * 6 = 5 + 6 + 19 = 30 (proven)
Mark M. answered • 02/04/17 Mathematics Teacher - NCLB Highly Qualified
The two integers are "n" and "n + 1." n(n + 1) = n + n + 1 + 19 Can you solve for "n" and answer the question? |