The population of a town three years ago was b and the population of the town

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Ohio State University

Julia V.

Algebra

3 months, 3 weeks ago

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The population of a town grows exponentially according to the function $$f(t)=12,400(1.14)^{t}$$ for $0 \leq t \leq 5$ years. Find, to the nearest hundred, the population of the town when $t$ is a. 3 years b. 4.25 years

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Question

The population of a town three years ago was ‘b’ and the population of the town three years from now will be ‘c’. What is the current population of the town, if it grows at the same rate? (a) √(bc) (b) b√(c) (c) c√(b) (d) b√(b/c) (e) √(b/c)

Answer

your correct answer is√bc

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a) square root of bc Late the population increases at the rate of r per year and present population is x, then b[1+(r/100)]^3 = x =>[1+(r/100)]^3 = x/b Also x[1+(r/100)]^3=c => x*x/b= c or x^2= bc
Hence x= Sqrt(bc)
5 years agoHelpfull: Yes(23) No(4)
From that Late the population increases at the rate of r per year and present population is x, then b[1+(r/100)]^3 = x =>[1+(r/100)]^3 = x/b Also x[1+(r/100)]^3=c => x*x/b= c or x^2= bc
Hence x= Sqrt(bc)
3 years agoHelpfull: Yes(1) No(1)