The LCM of two numbers is 210 and their HCF is 14 how many such pairs are possible

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Let the numbers be 14x and 14y 14x × 14y = 14 × 210 ⇒ xy = 210/14 = 30/2 = 15 x = 1, y = 15; x = 3, y = 5 (14, 210), (42, 70) Two pairs

The LCM of two numbers is 210 and their HCF is 14. How many such pairs are possible?

Product of two numbers = LCM × HCF
x × y = 210 × 14

x × y = 2940

(12, 245), (20, 147)

Two pairs possible.

2	2940
2	1470
5	735
7	147
7	21
	3

Concept: Relationship between the Numbers and their HCF and LCM

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