Changes made to your input should not affect the solution: Show (1): "x2" was replaced by "x^2". 2 more similar replacement(s). Step 1 :Equation at the end of step 1 :((((x4)+(2•(x3)))-13x2)-38x)-24Equation at the end of step 2 :((((x4) + 2x3) - 13x2) - 38x) - 24Step 3 :Polynomial Roots Calculator : 3.1 Find roots (zeroes) of : F(x) = x4+2x3-13x2-38x-24 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient In this case, the Leading Coefficient is 1 and the Trailing Constant is The factor(s) are: of the Leading Coefficient : 1
x4+2x3-13x2-38x-24 can be divided by 4 different polynomials,including by x-4 Polynomial Long Division : 3.2 Polynomial Long Division x4+2x3-13x2-38x-24 ("Dividend")
Quotient : x3+6x2+11x+6 Remainder: 0 Polynomial Roots Calculator :3.3 Find roots (zeroes) of : F(x) = x3+6x2+11x+6 See theory in step 3.1 In this case, the Leading Coefficient is 1 and the Trailing Constant is The factor(s) are: of the Leading Coefficient : 1
x3+6x2+11x+6 can be divided by 3 different polynomials,including by x+3 Polynomial Long Division : 3.4 Polynomial Long Division x3+6x2+11x+6 ("Dividend") By : x+3 ("Divisor")
Quotient : x2+3x+2 Remainder: 0 Trying to factor by splitting the middle term3.5 Factoring x2+3x+2 The first term is, x2 its coefficient is 1 . The middle term is, +3x its coefficient is 3 . The last term, "the constant", is +2 Step-1 : Multiply the coefficient of the first term by the constant 1 • 2 = 2 Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 3 .
x • (x+1) Add up the last 2 terms, pulling out common factors :2 • (x+1) Step-5 : Add up the four terms of step 4 :(x+2) • (x+1) Which is the desired factorization Final result :(x + 2) • (x + 1) • (x + 3) • (x - 4) |