If three coins are tossed simultaneously the probability of getting exactly two heads is

`3/8`

Explanation:

When 3 coins are tossed simultaneously, the possible outcomes are HHH, HHT, HTH, THH, THT, HTT, TTH and TTT.

Total number of possible outcomes = 8

Let E be the event of getting exactly two heads.

Then, the favourable outcomes are  HHT, THH, and HTH.

​Number of favourable outcomes = 3

∴ Probability of getting exactly 2 heads =  P(E) =`3/8` 

Text Solution

Answer : N/a

Solution : In a toss of three coins, <br> `S={HHH,HHT,HTH,THH,H"TT",THT,"TT"H,"TTT"}` <br> `implies` No. of possible `=8` <br> (i) Favourable outcomes of getting 2 heads <br> `={HHT,HTH,THH}` <br> No. of favourable outcomes of getting 2 heads `=3` <br> and probability of getting 2 heads `=3/8`. <br> (ii) Favourable outcomes of getting one head and two tails <br> `={H"TT",THT,"TT"H}` <br> No. of favourable outcomes of getting one head and two tails `=3` <br> and probability of getting on head and two tails <br> `=3/8` <br> (iii) Favourable outcomes of getting at least one head <br> `={H"TT",THT,"TT"H,HHT,HTH,THH,HHH}` <br> No. of favourable outcomes of getting at least one head `=7` <br> and probability of getting at least one head `=7/8`

three coins are tossed simultaneously. What is the probability of getting exactly two heads? a 1/2 b 1/4 c 3/8 d 3/4

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