Calculate the force between two alpha particles kept at a distance of 0.02 mm in air

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Text Solution

`90 N``45 N``60 N``75 N`

Answer : A

Solution : Here, `r= 3.2xx10^(-15)m` <br> charge on `alpha`-particle, `q_(1)=q_(2)= 2xx1.6xx10^(-19)C` <br> Now, `F= 1/(4piepsilon_(0))*(q_(1)q_(2))/(r^(2))` <br> `=9 xx 10^(9)xx((2xx1.6xx10^(-19))^(2))/((3.2xx10^(-15))^(2))=90 N`

Electric Charges And Fields

alpha particles hav +2e charge.. force= kq1q2/r

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