Ajay sold a computer for Rs 35000 at a Loss of 15 find the price at which ajay has purchased it

1. John buys an old scooter for $\text{Rs. }4700$ and spends $\text{Rs. }800$ on its repairs. If he sells the scooter for $\text{Rs. }5800,$ what is his gain percent?
A. $5\dfrac{5}{11}\%$	B. $10\%$
C. $4\dfrac{4}{7}\%$	D. $12\%$

answer with explanation

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Answer: Option A

Explanation:

cost price $=4700+800=5500$selling price $=5800$gain $=5800-5500=300$

gain percent $=\dfrac{300×100}{5500}$ $=\dfrac{60}{11}\%=5\dfrac{5}{11}\%$

2. The cost price of $20$ articles is the same as the selling price of $x$ articles. If the profit is $25\%,$ find the value of $x$
A. $16$	B. $15$
C. $25$	D. $18$

answer with explanation

Answer: Option A

Explanation:

Solution 1

reference: formula 1

$25=\dfrac{(20-x)100}{x}\\ \Rightarrow x=4(20-x)\\ \Rightarrow 5x=80\\ \Rightarrow x=16$

Solution 2

Let cost price of one article $=1$Then, cost price of $20$ articles $=20$Given that cost price of $20$ articles = selling price of $x$ articles.Therefore, selling price of $x$ articles $=20$$\Rightarrow$ selling price of $20$ articles $=\dfrac{20×20}{x}=\dfrac{400}{x}$

$20×\dfrac{125}{100}=\dfrac{400}{x}\\ \Rightarrow x=16$

Solution 3

Let cost price of one article $=1$selling price of $x$ articles= cost price of $20$ articles$=20$cost price of $x$ articles $=x$

$x×\dfrac{125}{100}=20\\ \Rightarrow x=16$

3. If selling price is doubled, the profit triples. What is the profit percent?
A. $105\dfrac{1}{3}\%$	B. $66\dfrac{2}{3}\%$
C. $120\%$	D. $100\%$

answer with explanation

Answer: Option D

Explanation:

Solution 1

Let cost price $=x$selling price $=y$Then, profit $=y-x$If selling price is doubled,selling price $=2y$profit $=2y-x$$2y-x=3(y-x)\\ \Rightarrow 2y-x=3y-3x\\ \Rightarrow y=2x$profit $=(y-x)=(2x-x)=x$

profit percent $=\dfrac{x×100}{x}=100\%$

Solution 2

If selling price is doubled, the profit triples.In this case, amount of increase in the selling price is equal to amount of increase in the profit. Therefore,selling price = $2$ × profit$\Rightarrow$ selling price - profit = profit$\Rightarrow$ cost price = profit

$\Rightarrow$ profit percent $=100\%$

Solution 3

($2$ sp - cp) $=3$(sp - cp)$\Rightarrow$ sp $=2$ cp$\Rightarrow$ sp - cp = cp$\Rightarrow$ profit = cp

$\Rightarrow$ profit percent $=100\%$

4. In a shop, the profit is $320\%$ of the cost. If the cost increases by $25\%$ but the selling price remains constant, find out approximately what percentage of the selling price is the profit?
A. $30\%$	B. $100\%$
C. $70\%$	D. $250\%$

answer with explanation

Answer: Option C

Explanation:

Let cost price $=100$Then, profit $=320$selling price $=100+320=420$new cost price $=125$profit $=420-125=295$Required percentage $=\dfrac{295×100}{420}$

$=\dfrac{1475}{21}\% \approx 70\%$

5. A vendor bought bananas at $6$ for a rupee. How many for a rupee must he sell to gain $20\%?$
A. $5$	B. $6$
C. $3$	D. $4$

answer with explanation

Answer: Option A

Explanation:

Solution 1

reference: formula 2Let required number $=x$

$20=\left(\dfrac{6×1}{x×1}-1\right)100\\ \Rightarrow \dfrac{1}{5}=\dfrac{6}{x}-1\\ \Rightarrow \dfrac{6}{5}=\dfrac{6}{x}\\ \Rightarrow x=5$

Solution 2

cost price of $6$ bananas $=1$gain $=20\%$selling price of $6$ bananas $=1×\dfrac{120}{100}=\dfrac{12}{10}$Number of bananas he should sell for $\text{Rs. }1$ for a gain of $20\%$

$=6×\dfrac{10}{12}=5$

Solution 3

cost price of $1$ banana $=\dfrac{1}{6}$gain $=20\%$selling price of $1$ banana $=\dfrac{1}{6}×\dfrac{120}{100}=\dfrac{1}{5}$Therefore, number of bananas he should sell for $\text{Rs. }1$ for a gain of $20\%$

$=5$

Set 1Set 2Set 3Set 4Set 5Set 6

in 2nd question solve in $\text{s.p}=\text{c.p}+\text{c.p}×\dfrac{\text{profit}\%}{100}$ in these formula using ans is $25$ but u take in $16$ how is come

a shop keeper sold a furniture for rs. 32000 and lost 20%. calculate the maximum retail price

Let the retail price be xhe lost 20% by selling it at 32000.that means he sold item at 80% of retail price.80x/100=32000x=40000

maximum retail price is 40,000

Let the retail price be xhe lost 20% by selling it at 32000.that means he sold item at 80% of retail price.80x/100=32000x=40000<p>maximum retail price is 40,000</p>

he lost 20% by selling it at 32000.that means he sold item at 80% of retail price.it is wrong to assume like this. The above statement means he sold item at 80% of cost price.

Cost price and Maximum Retail Price are different

he lost 20% by selling it at 32000.that means he sold item at 80% of retail price.it is wrong to assume like this. The above statement means he sold item at 80% of cost price.<p>Cost price and Maximum Retail Price are different</p>

Insufficient data

5% of 80% of rs 3000 is

80% of Rs.3000 = 3000*80/1005% of 80% of Rs 3000 = 3000*80/100 * 5/100 = 120

A man purchased 30 kg of rice at the rate of Rs. 17.5. per kg and another 30 kg rice at a certain rate. He mix the two and sold the entire quantity at the rate of Rs. 18.60/kg and made 20%overall profit.At what Price per kg did he purchased the lot of another 30 kg rice

Let the price per kg of the other 30 kg rice be xCost price is 30*17.5+30*x = 30(17.5+x)Selling Price = 60*18.60 = Rs.1116Profit is 20%Cost Price * 120/100 = Selling Price30(17.5+x) * 120/100 = 111617.5+x = 31

x = 13.5

Let me see who is smarter in this group. Answer if u can. A very simple but confusing puzzle.A lady buys goods worth rs.200 from a shop. (shopkeeper selling the goods with zero profit).The lady gives him 1000 rs note. The shopkeeper gets the change from the next shop and keeps 200 for himself and returns rs.800 to d lady. Later the shopkeeper of the next shop comes with the 1000rs note saying "duplicate" and takes his money back."How much LOSS did the shopkeeper face ?"A. 200B. 800C. 1200D. 1800E. 2000F. 1600

G. Other

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