A ray reflected successively from two plane mirrors inclined at a certain angle undergoes

a ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of 300. Then the angle is

a) 30 b) 60 c) 90 d 120

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A ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of $${ 300 }^{ 0 }$$, The number of observable image is $$O=360°-2θ$$$$300°=360°-2θ$$$$θ=30°$$no of images formed is $$n=(\dfrac{360°}{θ})-1$$$$n=(\dfrac{360°}{30}°)-1$$$$n=11$$

no. of images formed $$=11$$

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Answer : B

Solution : `delta=360^@-2theta` `theta:` angle between two mirrors `delta:` total angle of deviation after two reflection `240^@=360^@-2thetaimpliestheta=60^@` `x=(360^@)/(theta)=(360^@)/(60)=6` (even) Number of images, `n=x-1=6-1=5`

A ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of 300∘. The number of observable images are Formula for number of images is 360/θ 1, where θ is the angle between the mirrors.