Using equivalent ratios
Using multiples Using algebra Let $a$ be the number of apples and $o$ be the number of oranges at the beginning. Then we have that the ratio $a:o$ is $3:8$ and the ratio $a-1:o$ is $1:3.$ These give the simultaneous equations $8a=3o$ and $3(a-1)=o\Rightarrow 3a-3=o$Solving by elimination Multiplying both sides of $3a-3=o$ by $3$ gives $9a-9=3o$. Subtracting the equation $8a=3o$ from $9a-9=3o$ gives $$\begin{align}9a-9-8a&=3o-3o\\\Rightarrow a-9&=0\\\Rightarrow a&=9\end{align}$$ Substituting $a=9$ into $3a-3=o$ gives $o=3\times9-3=24.$Solving by substitution There will be 28 apples and 24 oranges; 52 - 4 = 48 ← this is now double the number of the fewer fruit 48 / 2 = 24 ← the number of the fewer fruit 24 + 4 = 28 ← the number of the fruit of which there are more 28 + 24 = 52 ← a check of the answer.
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