In the figure, ABC is a right angled triangle, right angled at B AD and CE are two medians

E and F are points on the sides PQ and PR respectively of a ∆PQR. For each of the following cases, state whether EF || QR:(i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm.(ii) PE = 4 cm, QE = 4.5 cm. PF = 8 cm and RF = 9 cm.(iii) PQ = 1.28 cm. PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm.

(i) We have,

In the figure, ABC is a right angled triangle, right angled at B AD and CE are two medians

From (i) and (ii), we have
In the figure, ABC is a right angled triangle, right angled at B AD and CE are two medians

Therefore, EF is not parallel to QR [By using converse of Basic proportionality theorem]
(ii) We have,
In the figure, ABC is a right angled triangle, right angled at B AD and CE are two medians

From (i) and (ii), we have
                
In the figure, ABC is a right angled triangle, right angled at B AD and CE are two medians

Therefore,      
In the figure, ABC is a right angled triangle, right angled at B AD and CE are two medians

 [Using converse of Basic proportionality theorem]

(iii) We have,


In the figure, ABC is a right angled triangle, right angled at B AD and CE are two medians

From (i) and (ii), we have
                       
In the figure, ABC is a right angled triangle, right angled at B AD and CE are two medians

Therefore,       
In the figure, ABC is a right angled triangle, right angled at B AD and CE are two medians

[Using converse of Basic proportionality theorem]

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