Find two numbers such that the mean proportional between them is 28 and proportional to them is 224.

Consider a and b as the two numbers

It is given that \[28\] is the mean proportional

\[a:\text{ }28\text{ }::\text{ }28:\text{ }b\]

We get

\[ab\text{ }=\text{ }{{28}^{2}}~=\text{ }784\]

Here \[a\text{ }=\text{ }784/b\]…… (1)

We know that \[224\] is the third proportional

\[a:\text{ }b\text{ }::\text{ }b:\text{ }224\]

So we get

\[{{b}^{2}}~=\text{ }224a\]….. (2)

Now by substituting the value of a in equation (2)

\[{{b}^{2}}~=\text{ }224\text{ }\times \text{ }784/b\]

So we get

\[\begin{array}{*{35}{l}}

{{b}^{3}}~=\text{ }224\text{ }\times \text{ }784  \\

{{b}^{3}}~=\text{ }175616\text{ }=\text{ }{{56}^{3}}  \\

b\text{ }=\text{ }56  \\

\end{array}\]

By substituting the value of b in equation (1)

\[a\text{ }=\text{ }784/56\text{ }=\text{ }14\]

Therefore, \[14\] and \[56\] are the two numbers.

Answer

Find two numbers such that the mean proportional between them is 28 and proportional to them is 224.
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Hint: In algebra, a mean proportional is a number that comes between two numbers . We used a mean proportional formula which is $\sqrt {ab} = $mean proportional. And the formula of third proportional $ac = {b^2}$.

Complete step-by-step answer:

Mean proportional of two number is given in the question but numbers are not So first we have to let a, b are the required numbers.Formula of mean proportional $\sqrt {ab} = $mean proportional$\sqrt {ab} = 28$Now take the square both side ${(\sqrt {ab} )^2} = {28^2}$$ab = 28.28$$ab = 784$So we can find the value of number a$a = \dfrac{{784}}{b}$ ……… equation (1)We have the third proportional given in the question that is 224The formula of third proportional $ac = {b^2}$$c = \dfrac{{{b^2}}}{a}$Put the values Here c is the third proportional$224 = \dfrac{{{b^2}}}{a}$Now put the value of a$224 = \dfrac{{{b^2}}}{{\dfrac{{784}}{b}}}$Simplifying the equation$224 = {b^2}.\dfrac{b}{{784}}$Multiply the R.H.S$224 = \dfrac{{{b^3}}}{{784}}$Apply the cross-multiplication method${b^3} = 224.784$${b^3} = $175616$b{ = ^3}\sqrt {175616} $$b = 56$So here we the second numberWe can find the first number a with the help of equation (1)$a = \dfrac{{784}}{b}$$a = \dfrac{{784}}{{56}}$$a = 14$Hence, we have both the numbers First is 14 and the second number is 56.

Note: In this type of question the most important point is calculation, always do the calculation carefully. We can check our answer by using a mean proportional method

Mean proportional =$\sqrt {a.b} $We have a = 14And b = 56After putting the values, we get= $\sqrt {14.56} $$ = \sqrt {784} $$ = 28$So here we get mean proportional that is already given in the question Our answer is correct by alternative checking method.

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The mean proportional between two numbers is 28 and their third proportional to them is 224 . The two numbers are

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Find two numbers such that the mean proportional between them is 28 and proportional to them is 224.

Find two numbers such that the mean proportional between them is 28 and proportional to them is 224.
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Question 11 Ratio and Proportion Exercise 7.2

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Find two numbers such that the mean proportional between them is 28 and proportional to them is 224.

Answer:

Consider a and b as the two numbers

It is given that 28 is the mean proportional

a: 28 :: 28: b

We get

ab = 28^{2} = 784

Here a = 784/b …… (1)

We know that 224 is the third proportional

a: b :: b: 224

So we get

\mathrm{b}^{2} = 224a ….. (2)

Now by substituting the value of a in equation (2)

\mathrm{b}^{2} = 224 × 784/b

So we get

\begin{array}{l} b^{3}=224 \times 784 \\ b^{3}=175616=56^{3} \end{array}

b = 56

By substituting the value of b in equation (1)

a = 784/56 = 14

Therefore, 14 and 56 are the two numbers.

Find two numbers such that the mean proportional between them is 28 and proportional to them is 224.
Find two numbers such that the mean proportional between them is 28 and proportional to them is 224.

Find two numbers such that the mean proportional between them is 28 and the third proportional to them is 224.

Let the two numbers are a and b.∵ 28 is the mean proportional∵ a : 28 : : 28 : b

∴ ab = (28)2 = 784

⇒ a = `(784)/b`             ...(i)∵ 224 is the third proportional∴ a : b : : b : 224

⇒ b2 = 224a         ...(ii)

Substituting the value of a in (ii)

b2 = `24 xx (784)/b`


⇒  b3 = 224 x 784
⇒ b2 = 175616 = (56)3∴ b = 56Now substituting the value of b in (i)a = `(784)/(56)` = 14

Hence numbers are 14, 56.

Concept: Concept of Proportion

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