Page 2
Four alternative answers for the following question is given. Choose the correct alternative. Two circles of radii 5.5 cm and 4.2 cm touch each other externally. Find the distance between their centres Let the two circles having centres P and R touch each other externally at point Q. Here, PQ = 5.5 cm, QR = 4.2 cm The two circles touch each other externally. ∴ By a theorem of touching circles, P−Q−R PR = PQ + QR ...[The distance between the centres of the circles touching externally is equal to the sum of their radii] = 5.5 + 4.2 = 9.7 cm ∴ The distance between the centres of the circles is 9.7 cm. Concept: Touching Circles Is there an error in this question or solution? Text Solution 2 cm `2.5` cm `1.5` cm 8 cm Solution : Let two circles with centres O and O' touch each other externally at the point C. The radius of the first circle is `5 cm therefore OC= 5cm,` and the radius of the second circle is 3 am, `therefore O'C=3cm.` <br> Now the distance between the centres of the circeles `=OO'= OC+CO' =5 cm +3 cm =8 cm` <br> `therefore `(d) is correct <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CBH_MAT_X_SOG_C04_SLV_016_S01.png" width="80%">
Get the answer to your homework problem. Try Numerade Free for 30 days
A circle with diameter $9.6 \mathrm{cm}$ has two parallel chords with lengths $5.2 \mathrm{cm}$ and $8.2 \mathrm{cm}$ How far apart are the chords? Find two possible answers. |