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The product of two consecutive integers is 19 more than their sum. Find the integers
The two consecutive integers can be written as:
x and x+1, where x is integer
The product of two consecutive integers is 19 more than their sum:
x(x + 1) = 19 + x + (x + 1)
by solving we find:
x1 = 5
x2 = -4
click here to see the step by step solution of the quadratic equation:
for x1 = 5
5 + 1 = 6
for x2 = -4
-4 + 1 = -3
there are two solutions:
first solution: the numbers are 5 and 6
second solution: the numbers are -4 and -3
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Amanda W. The product of two consecutive integers is 19 more than their sum. Find the integers.
2 Answers By Expert Tutors
Let the integers be X, and X + 1 X(X + 1) = X + (X + 1) + 19 from which we get X = -4 and 5 There are two possible sets of solutions the integers are = -4 and -4 + 1 or -4 and -3 (negative integers) or 5 and 5 + 1 or 5 and 6 (positive integers) check: -4*-3 = -4 + -3 + 19 = 12 (proven)
5 * 6 = 5 + 6 + 19 = 30 (proven)
Mark M. answered • 02/04/17
Mathematics Teacher - NCLB Highly Qualified
The two integers are "n" and "n + 1."
n(n + 1) = n + n + 1 + 19
Can you solve for "n" and answer the question?