Sol. Given, Initial velocity, u = 0 Final velocity, v =? Acceleration due to gravity, g = 9.8 m/s2 Height, h = 19.6 m We know that, v2 = u2 + 2gh = (0)2 + 2 × 9.8 × 19.6 = 19.6 × 19.6 = (19.6)2 = 19.6 m/s Therefore, its final velocity just before touching the ground is 19.6 m/s.
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A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground. Answer:
Given: u = Initial velocity of the stone = 0 v = Final velocity of the stone = ? s = Height of the tower = 19.6 m g = Acceleration due to gravity = 9.8 Using the third equation of motion, Hence, the velocity of the stone just before touching the ground is 19.6 .Related Questions for Study
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