AcademicMathematicsNCERTClass 10 Given: The angle of elevation of the top of tower, from the point on the ground and at a distance of 30 m from its foot, is $30^o$. To find: We have to find the height of tower. Solution: In the above image AB represents the tower, C is the point at a distance of $30\ m$ from foot of the tower and the angle of elevation of the top of tower from point C is $30^o$. Let height of tower be $h$ metre Now, In $\triangle ABC$, $tan\ 30^o\ =\ \frac{h}{30}$ $\Rightarrow \ \frac{1}{\sqrt{3}} \ =\ \frac{h}{30}$ $\Rightarrow \ h\ =\ \frac{30}{\sqrt{3} \ } \ =\ 10\sqrt{3}$ Therefore, the height of the tower is $10\sqrt{3}\ m$.
Updated on 10-Oct-2022 13:23:30
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