Option 3 : The force would be halved
10 Questions 10 Marks 10 Mins
CONCEPT:
\(\Rightarrow F \propto \frac{M_1M_2}{R^2} \Rightarrow F = \frac {GM_1M_2}{R^2} \) Where G = 6.674 × 10-11 m3Kg-1s-2 is a universal constant
CALCULATION: Given: Mass of the one body (M1) = M, Mass of the another body (M2) = 2M, initial distance = R, Final distance = 2R,F = Initial Force, F' = Final force M1 = M, M2 = 2M, R' = 2R \(\Rightarrow F \propto \frac{M_1M_2}{R^2}\) \(F'=\frac{GM_1M_2}{R'^2} =\frac{G M_1(2M_2)}{(2R)^2}=\frac {2GM_1M_2}{4R^2}=\frac {1}{2}F\) Hence, the Force would be halved is the correct answer. India’s #1 Learning Platform Start Complete Exam Preparation
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