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Ohio State University
Julia V.
Algebra
3 months, 3 weeks ago
We don’t have your requested question, but here is a suggested video that might help.
The population of a town grows exponentially according to the function $$f(t)=12,400(1.14)^{t}$$ for $0 \leq t \leq 5$ years. Find, to the nearest hundred, the population of the town when $t$ is a. 3 years b. 4.25 years
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This answer is categorized in the subject Math and for level Secondary School. 12 students answered this yesterday from cities such as Pithāpuram, Negapatam and Trichinopoly.
Question
The population of a town three years ago was ‘b’ and the population of the town three years from now will be ‘c’. What is the current population of the town, if it grows at the same rate? (a) √(bc) (b) b√(c) (c) c√(b) (d) b√(b/c) (e) √(b/c)
Answer
your correct answer is√bc
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CTS Company Numerical Ability Percentage
- a) square root of bc Late the population increases at the rate of r per year and present population is x, then
b[1+(r/100)]^3 = x =>[1+(r/100)]^3 = x/b
Also x[1+(r/100)]^3=c => x*x/b= c or x^2= bc
Hence x= Sqrt(bc)
- 5 years agoHelpfull: Yes(23) No(4)
- From that Late the population increases at the rate of r per year and present population is x, then
b[1+(r/100)]^3 = x =>[1+(r/100)]^3 = x/b
Also x[1+(r/100)]^3=c => x*x/b= c or x^2= bc
Hence x= Sqrt(bc)
- 3 years agoHelpfull: Yes(1) No(1)