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Let the numbers be 14x and 14y 14x × 14y = 14 × 210 ⇒ xy = 210/14 = 30/2 = 15 x = 1, y = 15; x = 3, y = 5 (14, 210), (42, 70) Two pairs
The LCM of two numbers is 210 and their HCF is 14. How many such pairs are possible?
Product of two numbers = LCM × HCF
x × y = 210 × 14
x × y = 2940
(12, 245), (20, 147)
Two pairs possible.
2 | 2940 |
2 | 1470 |
5 | 735 |
7 | 147 |
7 | 21 |
3 |
Concept: Relationship between the Numbers and their HCF and LCM
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